pbootcms中，提交表单后，希望跳转到对应的页面

1. 在template新建一个提交表单后，跳转的承接页面。这里命名为SuccessMessage.html
   
2. 同时，在后台新建一个栏目，专门放这个承接页面SuccessMessage.html
   
3. 最后在如下路径修改代码：core->function->helper.php。第161行，修改成如下代码：
   

echo '<script type="text/javascript">location.href="/SuccessMessage.html";</script>'; 

SuccessMessage.html代码如下：

{include file=comm/head01.html}
 <script>
 gtag('event', 'conversion', {'send_to': 'AW-10854549701/I8-JCPy_iKIDEMWR7bco'}); 
</script>
 <link href="{pboot:sitetplpath}/css/index.css" rel="stylesheet">
 {include file=comm/head02.html}


<div class="contactUs-main clearfix" style="height:calc(100vh - 457px)">
    <div class="contactUs-main-route"><a href="/">HOME</a> > Contact US</div>
    <div class="clearfix" style="margin:0 50%;">
        <img src="{pboot:sitetplpath}/images/face01.png" height="120">
        <p style="font-size: 18px;padding: 50px 0;width:500px">Submit Success!</p>
    </div>
</div>
{include file=comm/foot.html}
</body>
<script src="{pboot:sitetplpath}/js/index.js"></script>


<script language=javascript>
    function go()
    {
        window.history.go(-1);
    }
    setTimeout("go()",3000);
</script>
</html>